Problem Link : https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=260
Solution Idea : have to calculate factorial of n and then iterate through it and find values.
Solution :
#include<bits/stdc++.h>
#define ll long long
#define MAX 800
using namespace std;
ll int res[MAX];
ll int a[10];
ll int multiply(ll int x,ll int res_size);
void factorial(ll int n)
{
res[0] = 1;
ll int res_size = 1;
for (ll int x=2; x<=n; x++)
res_size = multiply(x, res_size);
for (ll int i=res_size-1; i>=0; i--)
a[res[i]]++;
}
ll int multiply(ll int x,ll int res_size)
{
ll int carry = 0;
for (ll int i=0; i<res_size; i++)
{
ll int prod = res[i] * x + carry;
res[i] = prod % 10;
carry = prod/10;
}
while (carry)
{
res[res_size] = carry%10;
carry = carry/10;
res_size++;
}
return res_size;
}
int main()
{
ll int n;
while(scanf("%lld",&n) and n)
{
memset(res,0,sizeof(res));
memset(a,0,sizeof(a));
factorial(n);
printf("%lld! --\n",n);
for(ll int i=0;i<=9;i++)
{
if(i!=4 and i!=9) printf("(%lld) %lld ",i,a[i]);
else printf("(%lld) %lld\n",i,a[i]);
}
}
}
Solution Idea : have to calculate factorial of n and then iterate through it and find values.
Solution :
#include<bits/stdc++.h>
#define ll long long
#define MAX 800
using namespace std;
ll int res[MAX];
ll int a[10];
ll int multiply(ll int x,ll int res_size);
void factorial(ll int n)
{
res[0] = 1;
ll int res_size = 1;
for (ll int x=2; x<=n; x++)
res_size = multiply(x, res_size);
for (ll int i=res_size-1; i>=0; i--)
a[res[i]]++;
}
ll int multiply(ll int x,ll int res_size)
{
ll int carry = 0;
for (ll int i=0; i<res_size; i++)
{
ll int prod = res[i] * x + carry;
res[i] = prod % 10;
carry = prod/10;
}
while (carry)
{
res[res_size] = carry%10;
carry = carry/10;
res_size++;
}
return res_size;
}
int main()
{
ll int n;
while(scanf("%lld",&n) and n)
{
memset(res,0,sizeof(res));
memset(a,0,sizeof(a));
factorial(n);
printf("%lld! --\n",n);
for(ll int i=0;i<=9;i++)
{
if(i!=4 and i!=9) printf("(%lld) %lld ",i,a[i]);
else printf("(%lld) %lld\n",i,a[i]);
}
}
}
No comments:
Post a Comment