Problem Link : https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1045
Solution idea : Straight forward extended euclid.
Solution :
#include<bits/stdc++.h>
#define ll long long
using namespace std;
ll int X=-1,Y=-1;
ll int ext_gcd (ll int A,ll int B){
ll int x2, y2, x1, y1, x, y, r2, r1, q, r;
x2 = 1; y2 = 0;
x1 = 0; y1 = 1;
for (r2 = A, r1 = B; r1 != 0; r2 = r1, r1 = r, x2 = x1, y2 = y1, x1 = x, y1 = y ) {
q = r2 / r1;
r = r2 % r1;
x = x2 - (q * x1);
y = y2 - (q * y1);
}
X = x2;
Y = y2;
return r2;
}
int main()
{
ll int a,b,e;
while(scanf("%lld%lld",&a,&b)==2)
{
e=ext_gcd(a,b);
printf("%lld %lld %lld\n",X,Y,e);
}
}
Solution idea : Straight forward extended euclid.
Solution :
#include<bits/stdc++.h>
#define ll long long
using namespace std;
ll int X=-1,Y=-1;
ll int ext_gcd (ll int A,ll int B){
ll int x2, y2, x1, y1, x, y, r2, r1, q, r;
x2 = 1; y2 = 0;
x1 = 0; y1 = 1;
for (r2 = A, r1 = B; r1 != 0; r2 = r1, r1 = r, x2 = x1, y2 = y1, x1 = x, y1 = y ) {
q = r2 / r1;
r = r2 % r1;
x = x2 - (q * x1);
y = y2 - (q * y1);
}
X = x2;
Y = y2;
return r2;
}
int main()
{
ll int a,b,e;
while(scanf("%lld%lld",&a,&b)==2)
{
e=ext_gcd(a,b);
printf("%lld %lld %lld\n",X,Y,e);
}
}
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